36x^2+49x=-8

Solution for 36x^2+49x=-8 equation:

36x^2+49x=-8

We move all terms to the left:

36x^2+49x-(-8)=0

We add all the numbers together, and all the variables

36x^2+49x+8=0

a = 36; b = 49; c = +8;
Δ = b2-4ac
Δ = 492-4·36·8
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{1249}}{2*36}=\frac{-49-\sqrt{1249}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{1249}}{2*36}=\frac{-49+\sqrt{1249}}{72}
$